Math, asked by awasthikshitiz28, 7 months ago

cos theta/sin(90°- theta)+cos(90°-theta) / sec(90°- theta) -3 tan^2 30°

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Answered by aditya0115

1

Answer:

cos theta/sin(90°- theta)+cos(90°-theta) / sec(90°- theta) -3 tan^2 30°

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