(cos theta + sin theta)² + (cos theta - sin theta)² =
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1
Answer:
Expanding the given expression we get
(cosA+sinA)2−(cosA+sinA)2
=cosA2+sinA2+2cosAsinA−(cosA2+sinA2−2cosAsinA)
=2(2cosAsinA)
=4cosAsinA
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Answered by
0
Answer:
2
cos^2 theta + sin^2 theta = 1
this is an identity
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