Math, asked by janvi294122, 10 months ago

cos theta sin theta - sin teta cos (90 - theta) cos teta /sec (90 - theta) - cos theta sin (90 - theta) sin theta /cosec (90-theta)

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Answers

Answered by Anonymous

cosθsinθ - sinθcos(90°-θ)cosθ/sec(90°-θ) - cosθsin(90°-θ)sinθ/cosec(90°-θ) +cosec(90°-θ)

⇒cosθsinθ - sinθsinθcosθ/cosecθ - cosθcosθsinθ/secθ - secθ

⇒cosθsinθ - sin³θcosθ- cos³θsinθ- secθ

⇒cosθsinθ(1-sin²θ - cos²θ) - secθ

⇒cosθsinθ(1-1) - secθ

⇒0 - secθ

⇒1/cosθ = RHS

pooja567958: gr8 answer

Answered by agrawalpriyanka68

Answer:

Step-by-step explanation:

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