Cos theta + sin theta square equal to 1 + sin 2 theta what is answer
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This result follows almost directly from the following:
(a+b)2=a2+2ab+b2
sin2(x)+cos2(x)=1
sin(2x)=2sin(x)cos(x)
With these, we have
(sin(x)+cos(x))2=sin2(x)+2sin(x)cos(x)+cos2(x)
=(sin2(x)+cos2(x))+2sin(x)cos(x)
=1+sin(2x)
(a+b)2=a2+2ab+b2
sin2(x)+cos2(x)=1
sin(2x)=2sin(x)cos(x)
With these, we have
(sin(x)+cos(x))2=sin2(x)+2sin(x)cos(x)+cos2(x)
=(sin2(x)+cos2(x))+2sin(x)cos(x)
=1+sin(2x)
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