Question

cos theta + sin theta / tan theta ×cot theta​

Answer 1

L.H.S. = sin θ tan θ/1 – cos θ = (sin θ. sin θ/cos θ) /1 - cos θ

= sin2 θ/cos θ(1 – cos θ)

= 1 – cos2θ/cos θ(1 – cos θ)

= (1 – cos θ)(1 + cos θ)/(cos θ(1 – cos θ)

= 1 + cos θ/cos θ = 1/cos θ + cos θ/cos θ

= sec θ + 1

= R.H.S.

Hope its help you.....