Question

cos thita =root 3/2,find sec thita​

Answer 1

Given  : sinθ=23

 Let us first draw a right △ABC,∠B=90 degrees and ∠A=θ

We know that sin θ=ACBC=Hypotenuse(perpendicular)=23

 By pythagoras Theorem:

 AC2=AB2+BC2

 or AB2=AC2−BC2=4k2−3k2=k2

AB=k

 Find other T-rations using their defination:

 cos=ACAB=21

 tanθ=ABBC=13

 cscθ=sinθ1=32

 secθ=cosθ1=2

 cotθ=tanθ1=31

Answer 2

sec thita =root 2/3 is the answer