Question

cos tita/ 1-sin tita- cos tita / 1+sin tita = 4​

Answer 1

Given, →cosx/1−sinx+cosx/1+sinx=4

→cosx[1/1−sinx+1/1+sinx]=4

→cosx[1+sinx+1−sinx(1−sinx)⋅(1+sinx)]=4

→2cosx1−sin2x=4

→cosxcos2x=2

→cosx=1/2