Question

Cos tita =√3/2 then find 4sin square tita +tan square tita

Answer 1

Answer:

4/3 cos tita B/H

$cos tita \sqrt{3} \div 2$

Psqure=hypo squre-base squre

${2}^{2} - { \sqrt{3} }^{2}$

4-3=1 =perpendicular=1

sin tita=p/H=1/2=tan tita=sin tita/cos tita=

$tan \: tita \: 1 \div \sqrt{3}$

$4 \div (1 \div {2)}^{2} + ( {1 \div \sqrt{3)} }^{2}$

1+1/3=4/3

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