Math, asked by khushi9570, 13 days ago

cos x . cos 2x . cos 3x = 1/4. Find all the solutions of the given equation using the formula
cos \alpha  . \cos(2 \alpha ) . \cos(3 \alpha ) .... \cos((n - 1)  \alpha ) =   \frac{\sin( {2}^{n}  \alpha ) }{ {2}^{n}sin \alpha  }
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Answers

Answered by tanishqaaraval05
0

Answer:

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