Math, asked by Anyxhaaa, 7 months ago

cos(x) + cos(π-x) =

Answers

Answered by MaheswariS
3

\textbf{To find:}

\textsf{The value of}

\mathsf{cosx+cos(\pi-x)}

\textbf{Solution:}

\mathsf{Consider,}

\mathsf{cosx+cos(\pi-x)}

\mathsf{Using,}

\boxed{\mathsf{cos(A-B)=cosA\,cosB+sinA\,sinB}}

\mathsf{=cosx+[cos\pi\,cosx+sin\pi\,sinx]}

\mathsf{=cosx+[(-1)cosx+(0)sinx]}

\mathsf{=cosx-cosx+0}

\mathsf{=0}

\implies\boxed{\mathsf{cosx+cos(\pi-x)=0}}

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