cos x + cos²x = 1 then
sin^8 x + 2 sin^6 x + sin^4 x =
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Answered by
1
Answer:
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Answered by
0
Answer: cos
x
+
cos
2
x
=
1
,
then
cos
x
=
1
−
cos
2
x
=
sin
2
x
.
sin
12
x
+
3
sin
10
x
+
3
sin
8
x
+
sin
6
x
+
2
sin
4
x
+
2
sin
2
x
−
2
=
cos
6
x
+
3
cos
5
x
+
3
cos
4
x
+
cos
3
x
+
2
cos
2
x
+
2
cos
x
−
2
=
cos
6
x
+
3
cos
5
x
+
3
cos
4
x
+
cos
3
x
=
cos
4
x
(
cos
2
x
+
3
)
+
cos
3
x
(
3
cos
2
+
1
)
=
cos
4
x
(
1
−
cos
x
+
3
)
+
cos
3
x
(
3
−
3
cos
x
+
1
)
=
(
1
−
cos
x
)
2
(
4
−
cos
x
)
+
cos
x
(
(
1
−
cos
x
)
(
4
−
3
cos
x
)
=
(
1
−
2
cos
x
+
1
−
cos
x
)
(
4
−
cos
x
)
+
cos
x
(
4
−
7
cos
x
+
3
−
cos
x
=
(
2
−
3
cos
x
)
(
4
−
cos
x
)
+
cos
x
(
7
−
10
cos
x
)
=
8
−
14
cos
x
+
3
cos
2
x
+
7
cos
x
−
10
cos
2
x
=
8
−
7
cos
x
−
7
cos
2
x
=
8
−
7
(
1
)
=
1
Step-by-step explanation: PLEASE MAKE ME THE BRAINLEIST
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