Question

cos x + sin ( 3pi/2+x) - sin (3pi/2-x) +cos (pi +x)=0

Answer 1

The answer is 0 because
Sin(270+x)=-cos x
Sin(270-x) = cos x
So cos x -cos x-cos x+cos x.
So answer is 0

Answer 2

Answer:

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Step-by-step explanation:

The given expression

= cos x + sin ( 270°+x) - sin (270°-x) +cos (180° +x)

= cos x + sin ( 3×90°+x) - sin ( 3× 90°-x) +cos (2×90° +x)

= cosx - cosx + cosx - cosx

= 0