Question

Cos0=0.6 show that sin0-3tan0=0

Answer 1

Step-by-step explanation:

Theta is written as @

cos @ = 0.6 = 6/10

cos @ =base/hypotenuse = 6/10 

by pythagoras theorem,

(6)^2 + (heigth)^2 = (10)^2

height^2 = 100-36

height^2= 64

height = 8

then 

5* sin @ = 5* height/hypotenuse = 5*(8/10) = 8/2 = 4 

and 

3* tan @ = 3*(height/base)  = 3*(8/6)= 8/2 =4

then,

(5 sin @ - 3tan @) = 0

4-4 = 0

0=0