Question

cos0/1-sin0+cos0/1+sin0​

Answer 1

Answer:

2sec0

Step-by-step explanation:

cos0/1-sin0+cos0/1+sin0

=>[cos0(1+sin0)+cos0(1-sin0)]\(1-sin0)(1+sin0)

=>[cos0+sin0+cos0-sin0]\1-sin^(2)0

[a^2-b^2=(a+b)(a-b) ]

=>2cos0/cos^(2)0

[sin^(2)0+cos^(2)0=1]

=>2/cos0

=>2sec0

mark as branliest if this answer is correct

i took 0 as theta