Question

cos0 sin (90-0)/tan (90-0).
+COSO. COS (90-0)​

Answer 1

Answer:

1

Step-by-step explanation:

cos theta.cos (90- theta)/tan(90-theta) + cos theta sin (90- theta)

=cos theta.sin theta /cot theta + cos theta cos theta

=cos theta.sin theta.sin theta/ cos theta + cos ^2 theta

= sin ^2 theta+ cos^2 theta

=1

Answer 2

Answer:

1

Step-by-step explanation:

[{cos∅×cos(90°-∅)}/tan(90°-∅)]+cos∅sin(90°-∅)

= [(cos∅sin∅)/cot∅]+cos²∅

=[(cos∅sin²∅)/cos∅]+cos²∅

= [cos∅sin²∅+cos³∅]/cos∅

= [cos(sin²∅+cos²∅)]/cos∅

= [cos∅/cos∅]

= 1

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