(Cos0°+cos45°+sin30°)(sin90°-cos45°+cos60°)
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Answer:
Explanation:
______________________
We know the values of
i) cos0° = 1
ii) sin45° =
iii) sin30° =
iv) sin90° = 0
v) cos45° =
vi ) cos60° =
_____________________
Now,
The value of
(cos 0+sin 45+sin 30)(sin 90-cos 45+cos 60)
=
=
=
/* By algebraic identity
(a-b)(a+b) = a²-b² */
=
=
=
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Answer is 1 . I hope it helps you
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