Question

(Cos0°+ sin45° +sin30°) (sin 90° - cos45° + cos60°)

Answer 1

Answer:

Step-by-step explanation:

Cos 0 = 1

Sin 45 = $\sqrt{2}$2 /2

Sin 30 = 1/2  

*

Sin 90 = 1

-

cos 45 = $\sqrt{2}$2 /2

+ cos 60 = 1/2

so :

Answer 2

Cos0=Sin90=1 sin45=cos45=1/root2,

Sin30=cos60=1/2,

According to question,

(Cos0+sin45+sin30) (sin90-cos45.+cos60)

=(1+1/root2+1/2)(1-1/root2+1/2)

= (1+root2/2+1/2)(1-root2/2+1/2)

= 4+4-2+1

= 7 —— Hence solved.