Question

(cos°45)/(sec30° + cosec30°)
please answer me fast... ​

Answer 1

1. 1/root2 divide by 2/root3+2
2. then u will get 1/root2 / 2+2root3 / 3
3. then simplify and u will get the answer as 3/2root2{1+root3}

Answer 2

Answer:

$cos45°= \frac{1}{ \sqrt{2} } \: , \: \: sec30° = \frac{2}{ \sqrt{3} } \: , \cosec30° = 2$

$\frac{cos45°}{sec30° + cosec30°} = \frac{ \frac{1}{ \sqrt{2} } }{ \frac{2}{ \sqrt{3}} + 2 } = \frac{ \frac{1}{ \sqrt{2} } }{ \frac{2 + 2 \sqrt{3} }{ \sqrt{3} } } = \frac{1}{ \sqrt{2} } \times \frac{ \sqrt{3} }{2 + 2 \sqrt{3} }$

$\frac{ \sqrt{3} }{2 + 2 \sqrt{5} } = \frac{3}{2 + 2 \sqrt{5} } \times \frac{2 - 2 \sqrt{5} }{2 - 2 \sqrt{5} }$

$\frac{3(2 - 2 \sqrt{5} )}{(2)^{2} - (2 \sqrt{5})^{2} } = - \frac{3(2 - 2 \sqrt{5}) }{16}$