Question

(cos0degree+sin30degree+sin45degree) (sin90degree+cos60degree -cos45degree)

Answer 1

Hiii friend,

Cos0° = 1

Sin30° = 1/2

Sin45° = 1/✓2

Sin90° = 1

Coa60° = 1/2

Cos45° = 1/✓2


Therefore,

(Cos0°+Sin30°+Sin45°)(Sin90°+Cos60°-Cos45°)

=> ( 1 + 1/2 + 1/✓2 ) ( 1 + 1/2 - 1/✓2)

=> (2✓2+✓2+2/2✓2) × (2✓2+✓2-2/2✓2)

=> (3✓2+2/2✓2) × (3✓2-2/2✓2)

=> (3✓2/2✓2 + 2/2✓2) × (3✓2/2✓2 + 2/2✓2)

=> (3✓2/2✓2)² - (2/2✓2)²

=> (3✓2)²/(2✓2)² - (2)²/(2✓2)²

=> 18/8 - 4/8

=> 18-4/8

=> 14/8 = 7/4



HOPE IT WILL HELP YOU..... :-)

Answer 2

(cos0+sin30+sin45)(sin90+cos60-cos45),=[1+.5+(1÷√2)][1+.5-(1÷√2)],
=[1.5+(1÷√2)][1.5-(1÷√2)],
=(1.5)^2-(1÷√2)^2,
=(9÷4)-(1÷2),
=7÷4