cos10cos50_sin10sin50
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Answered by
1
cos10cos50-sin10sin50
we know that,
cosAcosB-sinAsinB=cos(A+B)
so,
=cos(10+50)
=cos60°
=1/2
we know that,
cosAcosB-sinAsinB=cos(A+B)
so,
=cos(10+50)
=cos60°
=1/2
parwana:
thank you so much
Answered by
2
cos10cos50-sin10sin50
=cos(10+50)
=cos60
=1/2
formula used:
cos(A+B)=cosAcosB-sinAsinB
=cos(10+50)
=cos60
=1/2
formula used:
cos(A+B)=cosAcosB-sinAsinB
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