Question

cos12/13 then find sinA and tanA​

Answer 1

Step-by-step explanation:

Given

cos 12/13

To find

sin A and tan A

since we know that

cos= B/H

Then,

H^2 =p^2 + B^2 (formula)

13^2= p^2 +12^2

169 = p^2 +144

p^2=169-144

p^2=25

p=√25

p=5

since

sin A = p/H

=5/13

tan A =p/B

=5/12

ans.