Math, asked by Mayankmathuria, 1 year ago

Cos12-sin12/cos12+sin12=?

Answers

Answered by ArnavSuden
13

Dear Krisha

 

[cos(90-78) - sin12/ cos(90-78) + sin12 ] + sin147/cos147]

 

= [sin78 - sin12]/[sin78 + sin12]  +sin(180-33)/cos(180-33)

 

= [(2 cos 45 sin 33)/(2 sin 45 cos33)] + sin 33/(-cos 33)

 

Since cos 45 = sin 45, hence they can be cancelled

 

= Sin 33/ cos33  - sin 33/cos33

= 0

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