Question

Cos15 + sin15 / cos15 - sin15 find tha value

Answer 1

Step-by-step explanation:

$\frac{ \cos(15) + \sin(15) }{ \cos(15) - \sin(15) } \\ \\ \frac{\cos(15) + \sin(15)}{ \cos(15) - \sin(15) } \times \frac{\cos(15) + \sin(15)}{\cos(15) + \sin(15)} \\ \\ \frac{ ({\cos(15) + \sin(15))}^{2} }{ {cos}^{2} (15) - {sin}^{2} (15)} \\ \\ \frac{ {cos}^{2} (15) + 2 \cos(15) \sin(15) + {sin}^{2}(15) }{1 - {sin}^{2} (15) - { \sin }^{2} (15)} \\ \\ \frac{1 + 2 \cos(15) \sin(15) }{1 - 2 {sin}^{2}(15) } \\ \\ \frac{1 + 2 \cos(15) \sin(15)}{1 - 2 + 2 { \cos}^{2}(15) } \\ \\ \frac{1 + 2 \cos(15) \sin(15)}{2 { \cos }^{2} (15) - 1}$

Answer 2

$\Large\frak{\underline{\underline{Answer:}}}$

$\frac{ \cos(15) + \sin(15) }{ \cos(15) - \sin(15) } \\ \\ \frac{\cos(15) + \sin(15)}{ \cos(15) - \sin(15) } \times \frac{\cos(15) + \sin(15)}{\cos(15) + \sin(15)} \\ \\ \frac{ ({\cos(15) + \sin(15))}^{2} }{ {cos}^{2} (15) - {sin}^{2} (15)} \\ \\ \frac{ {cos}^{2} (15) + 2 \cos(15) \sin(15) + {sin}^{2}(15) }{1 - {sin}^{2} (15) - { \sin }^{2} (15)} \\ \\ \frac{1 + 2 \cos(15) \sin(15) }{1 - 2 {sin}^{2}(15) } \\ \\ \frac{1 + 2 \cos(15) \sin(15)}{1 - 2 + 2 { \cos}^{2}(15) } \\ \\ \frac{1 + 2 \cos(15) \sin(15)}{2 { \cos }^{2} (15) - 1}$