Question

cos15°cos45°2cosec75°​

Answer 1

Answer:

Step-by-step explanation:

$\cos15^\circ \cos45^\circ \times2\times cosec75^\circ\\\\=2\times \cos45^\circ \cos15^\circ \sec (90-75)^\circ\\\\= 2\times\frac{1}{\sqrt{2} } \cos15^\circ \sec15^\circ\\\\\bf= 2\times\frac{1}{\sqrt{2} } =\sqrt{2 }$