Math, asked by sanjaynadiyapara1907, 10 months ago

cos2 23° - sin2 67°​

Answers

Answered by souravchakraborty991
2

Answer:

cos2 23°-sin2 67°

=cos2 (90°-67°) - sin2 67°

=sin2 67°- sin2 67°

=0

Answered by Nitinsingh192
1

Answer:

 \cos2 \: 23 -  \sin2 \: 67 \\  \cos2 \: (90 - 67) -  \sin2 \: 67 \\  \sin2 \: 67 -  \sin2 \: 67 \\  =  > 0

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