cos2(26)+cos64sin26+tan36/cot54=x
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Answered by
14
Hey the answer is 1 , as ,
Cos2(26)+Cos(64)Sin(26)+Tan(36)\Cot(54) =
now , tan36\cot54 = 1
and , cos64×sin26 = sin²(26)
and , Cos2(26) = Cos²(26)-1
so, the eqñ will be :
Cos²26 + Sin²26 +1-1
Cos²26+Sin²26= 1
So, the answer is 1.
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Cos2(26)+Cos(64)Sin(26)+Tan(36)\Cot(54) =
now , tan36\cot54 = 1
and , cos64×sin26 = sin²(26)
and , Cos2(26) = Cos²(26)-1
so, the eqñ will be :
Cos²26 + Sin²26 +1-1
Cos²26+Sin²26= 1
So, the answer is 1.
Wish u Love It.
; )
mysticd:
Answer is 2
Plz , check
I think the first term is cos^2(26)
Answered by
4
U shud know all the formulas to solve problem easily. Just make sure that you are very clear abt the concepts of trigonometry as it will follow always follow you in physics and maths
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I think the first term is cos^2 (26)
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