cos² 67°-sin²23° fin the value
adithya02:
So you got the leaked paper on 27th huh
This question had come on 28th's math paper
saaale kutthe
now u anyway will have to write re exam so don't worry bwahahs
bwahaha*
Answers
Answered by
36
Hi ,
***************
We know that ,
Sin( 90 - A ) = cos A
*"**************************
Now ,
cos² 67° - sin² 23°
= cos² 67° - sin² ( 90 - 67 )
= cos² 67° - cos² 67°
= 0
I hope this helps you.
: )
***************
We know that ,
Sin( 90 - A ) = cos A
*"**************************
Now ,
cos² 67° - sin² 23°
= cos² 67° - sin² ( 90 - 67 )
= cos² 67° - cos² 67°
= 0
I hope this helps you.
: )
There is sin²(90°-23°)..... Not sin²(90°-67°)...
Hey guys... looks this guy abhikashyap got the leaked paper on 27th ... Coz this exact question came in the math paper on 28th
bcoz of such assh0les we innocent students have to suffer
Answered by
16
cos² 67-sin² 23°
= cos² 67°-sin²(90-67)
= cos² 67°-cos² 67 [Using identity sin(90-A) = cos(A)]
= 0
= cos² 67°-sin²(90-67)
= cos² 67°-cos² 67 [Using identity sin(90-A) = cos(A)]
= 0
Hey guys... looks this guy abhikashyap got the leaked paper on 27th ... Coz this exact question came in the math paper on 28th
looks like*
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