Question

cos²(80⁰ + teeta ) + sin²(100⁰ - teeta) =​

Answer 1

Answer:

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Answer 2

$\red{ The \: value \: of} \\\red{cos^{2} ( 80\degree + \theta ) + sin^{2} (100\degree - \theta) }$

$= cos^{2} (80\degree + \theta ) + sin^{2} [(180 - 80)\degree - \theta] \\= cos^{2} (80\degree + \theta )+ sin^{2} [180\degree-(80\degree + \theta)$

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$1.sin ( 180\degree - \theta ) = sin \theta$

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$= cos^{2} (80\degree + \theta ) + sin^{2} (80\degree + \theta )$

$= 1$

$\boxed { \pink { Since, Sin^{2}X + cos^{2} X = 1 }}$

Therefore.,

$\red{ The \: value \: of} \\\red{cos^{2} ( 80\degree + \theta ) + sin^{2} (100\degree - \theta) }\green {= 1 }$

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