Math, asked by sainimuskan172, 2 months ago

cos2 A + Sin A + Cos A + Tan A = 2 ( Sin A. Cos A)​

Answers

Answered by ITZURADITYAKING
2

Answer:

L.H.S=cosA(2cos2A−1)sinA(1−2sin2A)

L.H.S=cosA(2cos2A−1)sinA(1−2sin2A)Using multiple angle formula, cos2A=1−2sin2A=2cos2A−1

L.H.S=cosA(2cos2A−1)sinA(1−2sin2A)Using multiple angle formula, cos2A=1−2sin2A=2cos2A−1=cosAcos2AsinAcos2A

L.H.S=cosA(2cos2A−1)sinA(1−2sin2A)Using multiple angle formula, cos2A=1−2sin2A=2cos2A−1=cosAcos2AsinAcos2A=cosAsinA=tanA=R.H.S

Answered by gurmeetkaur19760
0

Step-by-step explanation:

First, change tan A to sin A/cos A then, cut cos^2 A with cos A and add the terms.

Attachments:
Similar questions