Cos2 alpha + cos 2 beta + cos 2 gama =??
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Answer:
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Explanation:
cos
2
xα+cos
2
β+cos
2
γ+1=0
asweknow
cos2A=2cos
2
A−1
cos
2
α+cos
2
β+cos
2
γ=1
now,
LHS
cos
2
α+ci=cos
2
β+cos
2
γ+1
2cos
2
α−1+2cos
2
β−1+2cos
2
γ−1+1
2(cos
2
α+cos
2
β+cos
2
γ)−3+1
2×1−2
2−2
0henceproved.
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