Math, asked by shubhamraj34866, 1 month ago

Cos2[log(x+7)] differenciation w.r.t.x plz answer me fast​

Answers

Answered by hrushikeshmore15
1

Answer:

x

2

+7

−2x⋅sin[2log(x

2

+7)]

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Step-by-step explanation:

Let y=cos

2

[log(x

2

+7)]

Differentiating w.r.t. x, we get

dx

dy

=

dx

d

{cos[log(x

2

+7)]}

2

=2cos[log(x

2

+7)]⋅

dx

d

{cos[log(x

2

+7)]}

=2cos[log(x

2

+7)]⋅{−sin[log(x

2

+7)]}⋅

dx

d

[log(x

2

+7)]

=−2sin[log(x

2

+7)]⋅cos[log(x

2

+7)]×

x

2

+7

1

dx

d

(x

2

+7)

=−sin[2log(x

2

+7)]×

x

2

+7

1

⋅(2x+0)…[∵2sinx⋅cosx=sin2x]

=

x

2

+7

−2x⋅sin[2log(x

2

+7)]

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