Cos2[log(x+7)] differenciation w.r.t.x plz answer me fast
Answers
Answered by
1
Answer:
x
2
+7
−2x⋅sin[2log(x
2
+7)]
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Step-by-step explanation:
Let y=cos
2
[log(x
2
+7)]
Differentiating w.r.t. x, we get
dx
dy
=
dx
d
{cos[log(x
2
+7)]}
2
=2cos[log(x
2
+7)]⋅
dx
d
{cos[log(x
2
+7)]}
=2cos[log(x
2
+7)]⋅{−sin[log(x
2
+7)]}⋅
dx
d
[log(x
2
+7)]
=−2sin[log(x
2
+7)]⋅cos[log(x
2
+7)]×
x
2
+7
1
⋅
dx
d
(x
2
+7)
=−sin[2log(x
2
+7)]×
x
2
+7
1
⋅(2x+0)…[∵2sinx⋅cosx=sin2x]
=
x
2
+7
−2x⋅sin[2log(x
2
+7)]
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