Question

cos² Q - 3 cos Q + 2 / sin Q = 1 ; find value of Q​

Answer 1

Answer:

Given: 2sin

2

θ=3cosθ

⇒2(1−cos

2

θ)=3cosθ

⇒2cos

2

θ+3cosθ−2=0

⇒2cos

2

θ+4cosθ−cosθ−2=0

⇒(2cosθ−1)(cosθ+2)=0

⇒cosθ=

2

1

and cosθ=−2 is not possible because cosθ≥−1

⇒cosθ=

2

1

⇒θ=

3

π

,

3

5π