cos²θ/sinθ
- cosec θ + sin θ= 0
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LHS=
sinθ
cos
2
θ
−cosecθ+sinθ
=
sinθ
cos
2
θ
−
sinθ
1
+sinθ
=
sinθ
cos
2
θ−1+sin
2
θ
=
sinθ
1−1
=0
=RHS
Hence proved
sinθ
cos
2
θ
−cosecθ+sinθ
=
sinθ
cos
2
θ
−
sinθ
1
+sinθ
=
sinθ
cos
2
θ−1+sin
2
θ
=
sinθ
1−1
=0
=RHS
Hence proved
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