Question

cos²0/
(1 – tan 0)
sin³/
(sin 0 - cos 0) = (1+sin 0 cos 0) prove that ​

Answer 1

[cos² theta/(1-tan theta)]+ sin³theta/(sin theta- cos theta)

=[cos²theta * cos theta/(cos theta- sin theta)] + sin³theta/(sin theta-cos theta)

= [cos³theta/(cos theta-sin theta)] - sin³theta/(cos theta-sin theta)

= (cos³theta-sin³theta/(cos theta- sin theta)

by using formula

(a³-b³) = (a-b)(a²+b²+ab)

=[(cos theta-sin theta)(cos²theta+sin²theta +sin theta cos theta)]/(cos theta-sin theta)

=(cos² theta+sin²theta+sin theta cos theta)

= 1+sin theta cos theta = RHS

Answer 2

Answer:

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Step-by-step explanation:

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