cos²0/sin0-cosec0 +sin0= 0
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Answered by
0
LHS=
cos ^2 θ/sinθ −cosecθ+sinθ
= sinθcos 2 θ
= cos ^2 θ / sinθ - 1 /sinθ +sinθ
= 1-1/sinθ
=0
=RHS
Hence proved
Answered by
1
Step-by-step explanation:
LHS = (cos^2 θ / sin θ) - cosec θ + sin θ
= (cos^2 θ / sin θ) - 1 / sin θ + sin θ
= cos^2 θ - 1 + sin^2 θ / sin θ
= 1 - 1 / sin θ
= 0 = RHS
Hence, proved.
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