cos20°cos40°cos60°cos80°=1/16
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The trick is to multiply by sin(20°) and repeatedly apply the double-angle identity sin(2x)=2sin(x)cos(x).
Let x = cos(20°)cos(40°)cos(80°).
x sin(20°) = sin(20°)cos(20°)cos(40°)cos(80°)
= 1/2 sin(40°)cos(40°)cos(80°)
= 1/4 sin(80°)cos(80°)
= 1/8 sin(160°)
= 1/8 sin(20°).
Therefore, x = 1/8.
then cos60x1/8=1/16
mahiraathani:
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Answer:
Step-by-step explanation:
Bcz 4Cosa.cos(60-a).cos(60+a)=cos3a
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