Math, asked by AkashChodisetty, 1 year ago

cos²33°-cos²57÷sin21°-cos21°

Answers

Answered by jaskaransinghse
6

[ (cos33-cos57)(cos33+cos57)]/(sin21-cos21... 

=[-2sin45sin(24)*2cos45cos24]/(cos69-c... 

=[-4*1/2*sin24cos24]/(-2sin45sin48) 

=[-2sin24cos24]/(-2/√2sin48) 

=[√2 sin48]/2sin48 
=1/√2 
2) sin51+sin9 
=2sin30*cos42 
=cos
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