Cos²40 + cos²50/ 2(Sin²59 + Sin²31) = 2/k
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13
Hey !!!
Explanation :- we know that the sin²¢ + cos²¢ = 1
similarly here we consider 50° as ¢ then in numerator will it will be sin²¢ + cos²¢ . ( but we know that sin²¢ + cos²¢ = 1 )
similarly in denomenator 31° considered as ¢ so sin²¢ + cos²¢ = 1 we get .
Note ↔ If you are asking to find value of k , then i hope my solution will help you !
Explanation :- we know that the sin²¢ + cos²¢ = 1
similarly here we consider 50° as ¢ then in numerator will it will be sin²¢ + cos²¢ . ( but we know that sin²¢ + cos²¢ = 1 )
similarly in denomenator 31° considered as ¢ so sin²¢ + cos²¢ = 1 we get .
Note ↔ If you are asking to find value of k , then i hope my solution will help you !
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Answered by
11
Cos²40 = Cos² ( 90 - 50 ) = Sin²50°
And,
Sin²31 = Sin² ( 90 - 59 ) = Cos² 59°
Therefore,
Cos²40° + Cos²50° / 2 ( Sin²59° + Cos²59° ) = 2/K.
2/ K = 1 / 2 × 1
2/ K = 1/2
K = 4.
And,
Sin²31 = Sin² ( 90 - 59 ) = Cos² 59°
Therefore,
Cos²40° + Cos²50° / 2 ( Sin²59° + Cos²59° ) = 2/K.
2/ K = 1 / 2 × 1
2/ K = 1/2
K = 4.
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