cos25° = t, Find sin 205° in term of t
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The value of Sin 205° = √(1+t²)
Given:
Cos 25° = t
To find:
Sin 205° in term of t
Solution:
Now we will find Cos 205° from Cos 25° = t
⇒ Cos (180+25)°
= - Cos 25°
= - t
⇒ Cos 205° = -t
As we know from trigonometric identities Sin²θ+ Cos²θ = 1
⇒ Sin²205° + Cos²205° = 1
⇒ Sin²205° = 1 - Cos²205°
⇒ Sin²205° = 1 - (-t)²
⇒ Sin²205° = 1 + t²
⇒ Sin 205° =
Therefore, the value of Sin 205° = √(1+t²).
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