Math, asked by faizahmedfreefirelov, 16 days ago

cos²60⁰+sin²30⁰+tan²60⁰/2. find the value​

Answers

Answered by MrFire07
6

Cos^2(60) + sin^2(30) + tan^2(60)/2

= (cos60)^2 + (sin30)^2 + (tan60)^2/2

= 1/4+1/4+3/2

= 2

Answered by vaibhavdantkale65
0

Answer:

sin

2

60

0

cos

2

30

0

+tan45

0

cos60

0

sin30

0

=sin

2

60

0

sin

2

60

0

+(1)cos

2

60

0

=sin

4

60

0

+cos

2

60

0

Substituting the values of sin60

0

and cos60

0

we get

(

2

3

)

4

+(

2

1

)

2

=

16

9

+

4

1

=

16

13

Hence answer is A

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