cos²60⁰+sin²30⁰+tan²60⁰/2. find the value
Answers
Answered by
6
Cos^2(60) + sin^2(30) + tan^2(60)/2
= (cos60)^2 + (sin30)^2 + (tan60)^2/2
= 1/4+1/4+3/2
= 2
Answered by
0
Answer:
sin
2
60
0
cos
2
30
0
+tan45
0
cos60
0
sin30
0
=sin
2
60
0
sin
2
60
0
+(1)cos
2
60
0
=sin
4
60
0
+cos
2
60
0
Substituting the values of sin60
0
and cos60
0
we get
(
2
3
)
4
+(
2
1
)
2
=
16
9
+
4
1
=
16
13
Hence answer is A
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