Math, asked by mervinjoseph, 1 year ago

cos28+sin28=k³then cos17=

Answers

Answered by OfficialPk
15
cos28+sin28=k^3
cos(90−62)+sin28=k^3
sin62+sin28=k^3
2sin(62+282)cos(62−282)=k^3
2sin45cos17=k^3
2×1/root2×cos17=k^3
√2×cos17=k^3
cos17=k^3/root2

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