Math, asked by anusuyasilwal, 8 months ago

cos2A/1+sin2A=1-tanA/1+tanA

Answers

Answered by sprao53413

3

Answer:

L. H. S=(cos^2 A- sin^2 A) /(sin^2 +cos^2A +2sinAcosA)

=(cosA - sinA) /(cosA+sinA)

Divide numerator and denominator by cosA

=1-tanA/1+tanA

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