Math, asked by tapandkbal2004, 23 days ago

(cos²A)³-(sin²A)³= cos2A(1-1/4sin²2A)​

Answers

Answered by amanraj56
1

Step-by-step explanation:

(cos²A)³-(sin²A)³

(cos²A-sin²A){(cos²A)²+(sin²A)²+sin²Acos²A}

cos2A(cos⁴A+sin⁴A+sin²Acos²A)

cos2A{(cos²A)²+(sin²A)²+sin²Acos²A}

cos2A{(cos²A+sin²A)²-2sin²Acos²A+sin²Acos²A}

cos2A(1²-sin²Acos²A)

cos2A{1-(4sin²Acos²A)/4}

cos2A{1-(2sinAcosA)²/4}

cos2A(1-sin²2A/4)

cos2A(1-1/4sin²2A)

#666

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