cos2a-3cosa+2/sin2a=1
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Cos2a-3cosA+2/sin2a= 1
[(Sin2a*cos2a)-(3cosA*sin2A)+2]/sin2A=1
(1+2+3cosA*sin2A)/sin2A=1
(3+3cosA-sin2A)/sin2A=1
sin2A/sin2A=1
1=1
Hence proved
[(Sin2a*cos2a)-(3cosA*sin2A)+2]/sin2A=1
(1+2+3cosA*sin2A)/sin2A=1
(3+3cosA-sin2A)/sin2A=1
sin2A/sin2A=1
1=1
Hence proved
NikitaRade:
But I didn't understand
Hi but this is the method of solving by formula thanks
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Answer:
the above ANSWER is correct
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