Question

(cos²A-3cosA+2)/(sin²A)=1
prove this.
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Answer 1

Rhs                             =  LHS

Cos2a-3cosA+2/sin2a= 1

[(Sin2a*cos2a)-(3cosA*sin2A)+2]/sin2A=1

(1+2+3cosA*sin2A)/sin2A=1

(3+3cosA-sin2A)/sin2A=1

sin2A/sin2A=1

1=1

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