(cos2A+9cosA+5)/(4+cosA)= (2cosA+1)
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Step-by-step explanation:
LHS
(cos2A+9cosA+5)/(4+cosA)
=(2cos²A-1+9cosA+5)/(4+cosA)
=(2cos²A+9cosA+4)/(4+cosA)
=(2cos²A+8cosA+cosA+4)/4+cosA
={2cosA(cosA+4)+1(cosA+4)}/4+cosA
=(2cosA+1)(cosA+4)/(cosA+4)
=(2cosA+1)
RHS
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