Math, asked by tasfiaramim, 10 hours ago

cos²A + cos²B+ 2cosA cosB cosC= sin^2C

Answers

Answered by hardiksingh8b

1

Step-by-step explanation:

cos^2a + cos^2b+ 2cosa cosb cos= sin^2c

cos2a+cos2b+2cosacosbcos=sin2c

Answered by dsn59751

0

Answer:

Mark me as brainiest answer

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