Question

cos2B-sin2B (when B=30°)​

Answer 1

$\star\:\:\:\sf\large\underline\blue{Question:-}$

• Evaluate $\sf\cos(2x) - \sin(2x)$ when $\sf x = 30 \degree$

$\star\:\:\:\sf\large\underline\blue{Solution:-}$

$\sf\cos(2x) - \sin(2x)$

$\sf = \cos(60 \degree) - \sin(60 \degree)$

$\sf = \frac{1}{2} - \frac{ \sqrt{3} }{2}$

$\sf = \frac{1 - \sqrt{3} }{2}$

$\star\:\:\:\sf\large\underline\blue{Answer:-}$

• $\sf\cos(2x) - \sin(2x) = \frac{1 - \sqrt{3} }{2}$

Answer 2

Answer:

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