Math, asked by aramf8018, 1 day ago

Cos2Q (1+tan2Q)+(1+cot2Q)sin2Q=2

Answers

Answered by arundhatisengupta8i2

0

Step-by-step explanation:

=sin2qcos2q(cos2q1+sin2q1)

=sin2qcos2q(sin2qcos2qsin2q+cos2q)

=sin2q+cos2q=1

Answered by susibaka12

0

Answer:

listen cos2*sec2Q+cosec2Q*sin2Q=2

Step-by-step explanation:

cos*sec=1

cosec*sin=1

AND!!

1+tan2Q=sec2Q

1+cot2Q=cosec2Q

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