cos²theta - sin²theta ≠ 2tan theta / 1- tan²theta
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Step-by-step explanation:
Hii friend,
Let @ be a theta.
Putting @ = 30° , we find
LHS = (Cos²@ - Sin²@)
= [(✓3/2)² - (1/2)²] = (3/4-1/4) = 2/4 = 1/2
RHS = 2tan30°/ 1 - tan²30°
= 2×1/✓3/[1-(1/✓3]² = 2/✓3/ 1-1/3 = 2/✓3 × 3/2 = ✓3.
THEREFORE,
LHS IS NOT EQUAL TO RHS.
HENCE,
THE GIVEN EQUATION IS NOT AN IDENTITY.
HOPE IT WILL HELP YOU and please follow me and mark me as brainliest
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